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Topic Review (Newest First)

07-08-2006 12:13 PM

Saynkuck123

Quote:

Originally Posted by roe

iirc, it's: [2(L x I x R)] / A

where:
L = wire length in meters
I = current in amps
R = resistance of cable in ohms
A = cross-section of cable in in millimeters squared

i'm not sure if it's the same calc that mik is talking about, but here's the one that i know of:
http://www.nooutage.com/vdrop.htm

By cross section do you mean the area of the conductor right? Why does the area of the cable matter anyway if you have the resistance of the cable per foot? I would think that a cable that has a cross sectional area of say 10kcmil that had a resistance of 1 ohm pre 1,000 feet, would have the exact same voltage drop as a cable with a cross sectional area of 5kcmil and a resistance of 1 ohm per 1,000 feet because the electrons would see the exact same amount of resistance in both cables.?

07-08-2006 11:37 AM

ROE

07-08-2006 10:59 AM

miklgagne

theres some web site that calculates it I forget what one, maybe if you search termpro. I've seen it before. It also has wattage lost in speaker wire too.

07-08-2006 10:36 AM

Saynkuck123

How do I calculate voltage drop across a wire?

I have been staring at the ohms law chart for the past 10 minuets and I just cant seem to figure it out. Maybe its because I am tired or my brain is tired of playing games for the past 8 hours. :P Anyway how do I calculate voltage drop in a circurt? I know the values for current resistance and starting voltage. I need to know the ending voltage across the circuit. I am trying to figure out how much voltage is lost in a run of wire.

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